256^(b+2)=4^2-2b

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Solution for 256^(b+2)=4^2-2b equation: 



256^(b+2)=4^2-2b

We move all terms to the left:

256^(b+2)-(4^2-2b)=0

We get rid of parentheses

256^(b+2)+2b-4^2=0

We add all the numbers together, and all the variables

2b+256^(b+2)-16=0

We move all terms containing b to the left, all other terms to the right

2b+256^(b+2)=16

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